I have built a regression model using SAS.

The R-square for the model is 0. I had built model using SAS; and obtained coefficients for each of predictors, and now I am computing predicted values as. It's range is 0 to 1. It indicates the amount of variance in the dependent variable accounted for by your predictor variable.

You can account for none of the variability. I can't read all of your formula, but you may be missing brackets or parenthese.

What computer program are you using? Are you still getting a -4 type of number for R2? I was thinking the problem might be that you had not put the ratio into parentheses or brackets to make sure the ratio was calculated first and then subtracted from one.

Now since the correlation is bounded between -1 and 1, it is impossible for R-square to be greater than 1. The formula i have used for R-square is.

Answer Save. Amy C. R-square is actually the correlation squared Now since the correlation is bounded between -1 and 1, it is impossible for R-square to be greater than 1. Should never be greater than 1. Still have questions? Get your answers by asking now.Documentation Help Center. Read an image with an object to segment. Convert the image to grayscale, and display the result.

## Why are correlations between -1 and 1?

This example shows how to segment an image into multiple regions. The example then computes the Dice similarity coefficient for each region. Create scribbles for three regions that distinguish their typical color characteristics. The first region classifies the yellow flower. The second region classifies the green stem and leaves. The last region classifies the brown dirt in two separate patches of the image. Regions are specified by a 4-element vector, whose elements indicate the x- and y-coordinate of the upper left corner of the ROI, the width of the ROI, and the height of the ROI.

The Dice similarity index is noticeably smaller for the second region. This result is consistent with the visual comparison of the segmentation results, which erroneously classifies the dirt in the lower right corner of the image as leaves.

Second binary image, specified as a logical array of the same size as BW1. First label image, specified as an array of nonnegative integers, of any dimension.

Second label image, specified as an array of nonnegative integers, of the same size as L1. First categorical image, specified as a categorical array of any dimension. Second categorical image, specified as a categorical array of the same size as C1.

Dice similarity coefficient, returned as a numeric scalar or numeric vector with values in the range [0, 1]. A similarity of 1 means that the segmentations in the two images are a perfect match.

If the input arrays are:. The Dice similarity coefficient of two sets A and B is expressed as:.If we can't tunnel through the Earth, how do we know what's at its center? A lady introduce her husband's name with saying by which can stop or move train what is that name.

Give points yo advocate thst biology is linked with physics chemistry mathsmatics geography. All Rights Reserved. The material on this site can not be reproduced, distributed, transmitted, cached or otherwise used, except with prior written permission of Multiply. Hottest Questions. Previously Viewed. Unanswered Questions. Can you have a probability greater than one? Wiki User Probability ranges from zero, meaning the event will not happen, to one, meaning the event will happen.

Related Questions Asked in Probability Why can't the probability be greater then one? A probability of 1 means something will definitely happen.

There cannot be a greater certainty than that, so probability cannot be greater than 1. Asked in Probability Can a probability be greater than 1? A probability can never be greater than 1.

Asked in Probability Why can't the probability of an event occurring be greater than 1? If probability becomes greater than one, then the uncertainty coefficient fluctuates and results in a terminal case.

Asked in Math and Arithmetic, Statistics, Probability What is the probability of rolling a number less than 3 and greater than 4 with one roll of a number cube?

The probability is zero.Have you tried factoring by grouping? It's not a trick and is not guess or check. It is doing double distributive in reverse. This is how I plan on teaching it next year! A friend showed it to me a few months ago, and I fell in love with it! Just saw this post -- I have always taught by grouping.

I teach grouping before doing this and then it is so easy for them.

### Source code for tensorlayer.cost

I have always used the double distributive method since they already understand distributive. Also, I make them draw arrows from the 1st set of parentheses to the 2nd -- 1st term, arrows above; 2nd term, arrows below.

We call them "rainbows". So now I say "Use your rainbows" and they remember! I love the box method because it is so much more organized than the table method. I also call it double distribution! I am going to look into grouping more I do teach it but for specific quadratics. They usually remark that the box method is so much more organized than all the arrows. Make this teacher's heart happy. As I'm preparing to teach factoring to my 9th grade Algebra students, I stumbled on this post.

It sounds like you use the box method for multiplying binomials It's a nice visual set up of the grouping method. I've tried slide and divide in the past though I like the "bottoms up" name better! That way, when they look back at the original problem, they don't mistakenly look at the "slide" version and forget to divide. Also, I've found it helpful to have students do the "divide" part with the numbers still in the diamond.

They seem less likely to forget that step when we set it up that way.

I've seen on several of your posts comments about factoring by grouping. Do you have any ISNB pages for factoring by grouping? Or a blog post about teaching it? I am getting ready to teach our polynomial unit which includes factoring. Tabitha, I'm not Sarah, but I'd be glad to share with you what I have if you want to share your email address.By using our site, you acknowledge that you have read and understand our Cookie PolicyPrivacy Policyand our Terms of Service.

The dark mode beta is finally here. Change your preferences any time. Stack Overflow for Teams is a private, secure spot for you and your coworkers to find and share information. As shown in the picture. I have tried adding K. I feel that since the output is sigmoid activated whether adding K.

Also, as you can see my accuracy is weird, I have been relying on dice to judge my model performance, would be greater if someone can point out the issue. Or that they have a single channel instead of 3 channels? Learn more. Dice coef greater than 1 Ask Question. Asked 2 months ago. Active 2 months ago. Viewed 37 times. Check this. Maybe you could share your model. You are right!!! Active Oldest Votes. I used "channel first" data format. May I know why should I use image dice?

The problem is not batch dice. You could even try a channel dice, since you have 3 channels there. Sign up or log in Sign up using Google. Sign up using Facebook. Sign up using Email and Password. Post as a guest Name. Email Required, but never shown. The Overflow Blog.

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Permalink Dismiss Join GitHub today GitHub is home to over 40 million developers working together to host and review code, manage projects, and build software together. Sign up. Branch: master. Find file Copy path. Raw Blame History. Following layers will contain a multiple of this number. Lowering this number will likely reduce the amount of memory required to train the model. The greater the depth, the more max pooling layers will be added to the model.

Lowering the depth may reduce the amount of memory required for training. This will be decayed during training. This increases the amount memory required during training. You signed in with another tab or window. Reload to refresh your session. You signed out in another tab or window. Builds the 3D UNet Keras model.

Lowering this number will likely reduce the amount of memory required. The greater the depth, the more max pooling. The x, y, and z sizes must be.

### Sørensen–Dice coefficient

Each level has a particular output shape based on the number of filters used in that level and the depth or number.The secrets of the ellipse. Toric sections.

Follow sfera But what if you want to find the probability of, say, a sum of 31 when rolling 10 dice, where simple enumeration would require a very long time? Or to find a more general formula for the probability of getting p points as the sum of rolling n dice? Is there such a formula, computable without having to enumerate all the cases? In combinatorics there are many different naming conventions and symbols, also coming from different cultural traditions.

Here is the meaning of the main notation and terminology used in this article. A set is a unordered collection of distinct objects. The cardinality S of a set S is the number of members of S. A subset is a portion of a set. A multiset is a unordered collection of objects in which members are allowed to appear more than once.

The number of times an element is repeated in the multiset is the multiplicity of that member. The total number of elements in a multiset, including repeated memberships, is the cardinality of the multiset.

On the contrary a list or tuple is an ordered sequence of objects.

**Aleks - Finding the roots of a quadratic with leading coefficient greater than 1**

A The permutations of the set S are the different possible ordered sequences of all the elements of S. If the set S has n elements, then the number of all possible different permutations of this set is:. In fact there are n possible choices for the element in the first position, for each of these there are n — 1 choices for the element in the second position since one of the n elements has already been used and so on till filling all n positions.

B Another different case of permutations this time with repetition occur when, instead of choosing the elements from a set S that, as such, has unique and distinguishable elements we choose them from a multiset M in which members are allowed to appear more than once.

In this case a multiset permutation is a sequence of all the elements of M in which each element appears exactly as often as is its multiplicity in M. If the multiplicities of the elements of M taken in some order are and their sum the cardinality of M is nthen the number of multiset permutations of M multinomial coefficient is given by: A typical example is that of the number of different anagrams of a word with some duplicate letter.

In case not all of the n elements of the collection are included in the permutations and we take only k elements out of the n available we have the k -permutations repetitions not allowed and the permutation with repetitions repetitions allowed detailed herebelow.

C k -permutations or variations are the ordered sequences of k elements taken from a set S of n elements. In other words k -permutations are those ordered arrangements in which no element occurs more than once, but without the requirement of using all the elements from a given set. The concept of k -permutations is then a generalization of that of permutations.

For example there are possible arriving orders of the first 3 horses in a race with 8 runners. As a special case, If k equals nwe get back to the notion of permutations.

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A combination is a selection of elements from a collection, where unlike permutations order does not matter. Since the order of the elements is not taken into account, two lists with the same elements but with different orderings are considered to be the same combination.

For example the number of different basketball teams of 5 players that can be formed from a group of 9 players is. The number of possible combinations with repetition multiset coefficient is:.

How many different ice creams will there be? The number of possible ice creams we could have is then:. This example is part of a more general kind of problems about finding the number of possible ways to distribute k indistinguishable objects balls, pencils, white t-shirts…in n containers, implicitly assuming that, after the distribution, some of the containers might remain empty or contain more objects even all.

Furthermore the number k of objects to distribute in the containers may be greater, equal or less than the number of containers n. The formula answering this question is:. So the analogy is built upon the fact that a ball in a box can be interpreted as a pointer to mean that that particular box has been chosen one or more times. Every other possible distribution could be translated in this way by a proper sequence of the two symbols and every sequence of the two symbols represents a different balls distribution.

So the problem of the distribution of 3 balls in 5 boxes can be translated in the possible different multiset permutations of 2 symbols, forming a sequence of length 7. So the multiset has cardinality 7 and is formed by two elements with multiplicity 3 and 4.

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